56 lines
1.7 KiB
Python
56 lines
1.7 KiB
Python
# -*- coding: utf-8 -*- #
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# Copyright 2015 Google LLC. All Rights Reserved.
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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"""Utilities for making requests using a given client and handling errors.
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"""
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from __future__ import absolute_import
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from __future__ import division
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from __future__ import unicode_literals
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import io
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from googlecloudsdk.core.resource import resource_printer
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def ExtractErrorMessage(error_details):
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"""Extracts error details from an apitools_exceptions.HttpError.
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Args:
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error_details: a python dictionary returned from decoding an error that
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was serialized to json.
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Returns:
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Multiline string containing a detailed error message suitable to show to a
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user.
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"""
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error_message = io.StringIO()
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error_message.write('Error Response: [{code}] {message}'.format(
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code=error_details.get('code', 'UNKNOWN'), # error_details.code is an int
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message=error_details.get('message', '')))
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if 'url' in error_details:
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error_message.write('\n' + error_details['url'])
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if 'details' in error_details:
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error_message.write('\n\nDetails: ')
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resource_printer.Print(
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resources=[error_details['details']],
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print_format='json',
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out=error_message)
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return error_message.getvalue()
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